wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, ABQP and ABCD are two parallelograms on the same base AB. Area of parallelogram ABCDArea of triangle PAB is equal to:


__

Open in App
Solution

ABQP is a parallelogram. Therefore,
ar(PAB)=12ar(ABQP) (since diagonal of a parallelogram divides it into 2 equal areas)
But, ar(ABQP) = ar(ABCD) (parallelograms on the same base and between the same parallels)
Therefore, ar(ABCD)=2×ar(PAB)
Hence,Area of parallelogram ABCDArea of triangle PAB=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Triangles between same parallels
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon