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Question

In the given figure, ABQP and ABCD are two parallelograms on the same base AB. Area of parallelogram ABCDArea of triangle PAB is equal to:


A

2

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B

3

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C

4

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D

6

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Solution

The correct option is A

2


In the figure,ABQP is a parallelogram.
Therefore,
ar(PAB)=12ar(ABQP) (since diagonal of a parallelogram divides it into 2 equal areas)
But, ar(ABQP) = ar(ABCD) (parallelograms on the same base and between the same parallels)
ar(ABCD)=2×ar(PAB)
Hence, Area of parallelogram ABCDArea of triangle PAB=2.


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