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Question

Question 6
In the given figure, AC = AE, AB = AD and BAD=EAC. Show that BC = DE.

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Solution

It is given that BAD=EACBAD+DAC=EAC+DAC[AddingDAC on both sides]BAC=DAE,In ΔBAC and ΔDAE,AB=AD(Given)BAC=DAE(Proved above)AC=AE(Given)ΔBACΔDAE(By SAS congruence rule)BC=DE (By CPCT)

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