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Question
In the given figure, AC = CE and AB || ED. The value of x is :
In the given figure, AC = CE and AB || ED. The value of x is :
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Solution
The correct option is B 15
In Δ ABC and Δ EDC
AC = CE (Given)
∠ BAC = ∠ DEC (Since AB||DE and AE is a transversal, so they are alternate angles)
∠ ACB = ∠ ECD (Vertically opposite angles)
∴ Δ ABC ≅ Δ EDC (ASA congruence criteria)
∴ AB = DE (Sides of congruent triangles)
∴ x+10 = 2x - 5
⇒ x = 15 units
In Δ ABC and Δ EDC
AC = CE (Given)
∠ BAC = ∠ DEC (Since AB||DE and AE is a transversal, so they are alternate angles)
∠ ACB = ∠ ECD (Vertically opposite angles)
∴ Δ ABC ≅ Δ EDC (ASA congruence criteria)
∴ AB = DE (Sides of congruent triangles)
∴ x+10 = 2x - 5
⇒ x = 15 units
Suggest Corrections
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