In the given figure, AC = CE and AB ∥ ED. The value of x is
In ΔABC and ΔEDC,AC=CE (given)∠BAC=∠DEC (since AB||DE and AE is a transversal, so they are alternate angles)∠ACB=∠ECD (vertically opposite angles)∴ΔABC≅ΔEDC (A.S.A. congruence criteria)∴AB=DE (sides of congruent triangles)∴x+10=2x−5⇒x=15 units