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Question

In the given figure AC is the diameter of the circle. If arc AXB is equal to half of arc BYC. \(\angle AOB\) = ___ degrees


\( \theta \)

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Solution

Given arc BYC is twice of arc AXB.

arc BYC : arc AXB = 2 : 1

BOC : AOB = 2:1

Angle made by arc AYC is 180o ( since AC is the diameter)

AOB = 13 × 180o

AOB = 60o


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