In the given figure, acceleration of 4 kg block is
(Take g=10m/s2)
A
3 m/s2
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B
2.5 m/s2
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C
2 m/s2
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D
3.5 m/s2
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Solution
The correct option is B 2.5 m/s2 Maximum frictional force experienced by block of 2 kg = μN = μmg = 0.8×2×10 = 16 N.
Since the force applied is less than maximum frictional force, hence both the blocks move together.
By F =15 N, acceleration is a=Fm1+m2 =152+4 =2.5m/s2