In the given figure, acceleration of 4 kg block is (Take g=10m/s2)
A
3 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.5 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 2.5 m/s2 Maximum frictional force experienced by block of 2 kg = μN = μmg = 0.8×2×10 = 16 N. Since the force applied is less than maximum frictional force, hence both the blocks move together. By F =15 N, acceleration is a=Fm1+m2 =152+4 =2.5m/s2