In the given figure, AD=AC. If $∠ A = 88^{o}$ , then $∠ A C D$ =

46^{o}

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44^{o}

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45^{o}

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Cannot be found

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Solution

The correct option is A $46^{o}$
$∠ A C D = \frac{180^{o} - 88^{o}}{2} = \frac{92^{o}}{2} = 46^{o}$

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∠ A C E = 30^{o}, ∠ A D B = 45^{o}, C E = 12 m

C D = 10 m .

A D

In the given figure, BD = AD and DC = AC, If $∠ A B C = 35^{\circ},$ then $∠ A C D = ?$

In the given figure, $A B > A C .$ Then, which of the following is true?

(a) AB < AD

(b) AB = AD

(d) Cannot be determined

△ A B D ≅ △ A C D

△ A B E ≅ △ A C D

△ A D E \sim △ A B C

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