Question

In the given figure, AD and CE are medians and DF//CE. Hence: $FB=\frac{1}{4}AB$
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Given: D and E are mid points of BC and AB respectively. $DF\parallel CE$
In $△BEC$,
$FD\parallel CE$ and D is mid point of BC
Hence, by converse of mid point theorem, F is mid point of BE.
Hence, $FB=\frac{1}{2}\left(BE\right)$
$FB=\frac{1}{2}\left(\frac{1}{2}AB\right)$ (E is mid point of AB)
$FB=\frac{1}{4}AB$