In the given figure, $A D = B C = 5 c m, A B = 4 c m, C D = 10 c m$ . What is the length of CF if B is the midpoint of ED and EF $⊥$ DF?

3 cm

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4 cm

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5 cm

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7 cm

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Solution

The correct option is B 4 cm

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\frac{D F}{F E} = \frac{A D}{A E}

In the figure given below AB = 3 cm, AC = 5 cm and AD = 4 cm and D is the midpoint of BC. Then the length of BD is :

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