In the given figure, AD=BC, ΔABC≅ΔADC by which the following congruency?
SSS
SAS
RHS
ASA
It is given that, AD=BC [given] also, AC=AC [common side] and, ∠ADC=∠ABC=90∘ [given] Therefore, ΔABC≅ΔADC by RHS congruency.
In the given figure, if ∠ ABC = ∠ ADC and ∠ BAC = ∠ DAC, then by which postulate is △ABC≅△ADC ?
In the given figure, if AB = DC and BC = AD, then by which postulate is △ABC≅△CDA ?
In the given figure, BC=DC and ∠ABC and ∠ADC are right angles. Which of the following statements are correct?