wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, AD = DB and AE = EC. Then, BC:DE=___.


Open in App
Solution

It is given that, AD = DB
i.e., AD = 12 AB

Also, as AE = EC
we have, AE = 12 AC

By mid-point theorem, we know that the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.
i.e., DE || BC and DE =
12 BC
Thus, BC : DE = 2 :1

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Mid-Point Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon