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Question

In the given figure, AD is a median of ABC and E is the mid-points of AD. Also, BE produced meets AC in F. Then AF =

A
3AC
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B
12AC
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C
2AC
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D
13AC
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Solution

The correct option is D 13AC
Draw DPEF
In ΔADP, E is the mid-point of AD and EFDP
F is the mid-point of AP.
In ΔFBC,
D is the mid-point of BC and DPBF.
P is the mid-point of FC
Thus, AF = FP = PC
Hence, AF =13AC


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