wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, AD is a median of ABC and E is the mid-points of AD. Also, BE produced meets AC in F. Then AF =

A
3AC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12AC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2AC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13AC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 13AC
Draw DPEF
In ΔADP, E is the mid-point of AD and EFDP
F is the mid-point of AP.
In ΔFBC,
D is the mid-point of BC and DPBF.
P is the mid-point of FC
Thus, AF = FP = PC
Hence, AF =13AC


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Converse of Pythagoras' Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon