In the given figure, AD is a median of ABC and E is the mid-points of AD. Also, BE produced meets AC in F. Then AF =
A
3AC
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B
12AC
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C
2AC
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D
13AC
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Solution
The correct option is D13AC Draw DP∥EF
In ΔADP, E is the mid-point of AD andEF∥DP ∴F is the mid-point of AP.
In ΔFBC, D is the mid-point of BC and DP∥BF. ∴P is the mid-point of FC Thus, AF = FP = PC
Hence, AF =13AC