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Question

In the given figure, AD is a median of ABC and E is the mid-points of AD. Also, BE produced meets AC in F. Then AF = ___


A

3AC

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B

12AC

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C

2AC

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D

13AC

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Solution

The correct option is D

13AC


Draw DPEF

In ΔADP, E is the mid-point of AD and EFDP

F is the mid-point of AP.

In ΔFBC, D is the mid-point of BC and DPBF.

P is the mid-point of FC

Thus, AF = FP = PC

Hence, AF =13AC


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