In the given figure AD is altitude to triangle ABC, then which of the following is correct?

∠ A D C

90^{\circ}

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BD = CD

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AB = AC

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∠ A B D

∠ A C D

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Solution

The correct option is A $∠ A D C$ = $90^{\circ}$
As given,
AD is altitude and altitude is the perpendicular drawn from the vertex of the triangle to its opposite side.

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In the given figure AD is altitude to triangle ABC, then which of the following is correct?

The correct option is A ∠ADC= 90∘As given, AD is altitude and altitude is the perpendicular drawn from the vertex of the triangle to its opposite side.

The correct option is A $∠ A D C$ = $90^{\circ}$
As given,
AD is altitude and altitude is the perpendicular drawn from the vertex of the triangle to its opposite side.