Question

In the given figure, all the batteries are ideal. Find the value of $i$ (in ampere)

Answer 1

By voltage divider rule, $i_1=0\text{A}$
$i_2=\frac{0-30}{6}=-5\text{A}$
$i_3=\frac{0-7}{7}=-1\text{A}$

Net current of the circuit, $i_1+i_2+i_3+i=0$

$0+-5-1+i=0$

$i=6\text{A}$