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Question

In the given figure, all triangles are equilateral and AB=8 units. Other triangles have been formed by taking the mid-points of the sides. What is the perimeter of the figure?


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Solution

Firstly, find the all outer sides of the given triangles and then find the perimeter by using sum of all sides of the triangles.

Given, ABC is an equilateral triangle.

Here, AB=8 units

AB=BC=CA=8 units.

Since, ABC is an equilateral triangle, then the triangle formed by mid-points of the sides is also an equilateral triangle.

Thus, ADE is an equilateral triangle.

Here, E is the mid-point of AB.

AE=BE=AB2=82=4 units

Now, in ADE,

AD=DE=EA=4 units

Similarly, BOT and UPC are equilateral triangles and having each sides equal.

i.e., BO=OT=BT=UC=PC=PU=4 units

It is also clear that, OC=PA=4 units

Also, DIF is an equilateral triangle.

Here, F is the mid-point of DE.


DF=FE=DE2=42=2 units

In DIF, DI=IF=DF=2 units

Similarly, in TKN and RQU,

TK=KN=TN=RQ=UQ=UR=2 units

it is also clear that, NC=RP=2 units

Also, HIG is an equilateral triangle.

Here, G is the mid-point of IF.

IG=GF=IF2=22=1 unit

Similarly, in MLK and XQS,

ML=MK=LK=SQ=XS=QX=1 unit

it is also clear that, LN=XR=1 unit

Now, perimeter of the given figure

= Sum of all outer sides of the given figure

=AD+DI+IH+HG+GF+FE+EB+BT+TK+KM+LM+LN+NO+OC+CU+UQ+QS+XS+XR+PR+PA

=[4+2+1+1+1+2+4+4+2+1+1+1+2+4+4+2+1+1+1+2+4] cm

=45 cm

Hence, the perimeter of the given figure is 45 cm.


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