In the given figure, all triangles are equilateral and AB=8 units. Other triangles have been formed by taking the mid-points of the sides. What is the perimeter of the figure?
Firstly, find the all outer sides of the given triangles and then find the perimeter by using sum of all sides of the triangles.
Given, △ABC is an equilateral triangle.
Here, AB=8 units
⇒AB=BC=CA=8 units.
Since, △ABC is an equilateral triangle, then the triangle formed by mid-points of the sides is also an equilateral triangle.
Thus, △ADE is an equilateral triangle.
Here, E is the mid-point of AB.
⇒AE=BE=AB2=82=4 units
Now, in △ADE,
AD=DE=EA=4 units
Similarly, △BOT and △UPC are equilateral triangles and having each sides equal.
i.e., BO=OT=BT=UC=PC=PU=4 units
It is also clear that, OC=PA=4 units
Also, △DIF is an equilateral triangle.
Here, F is the mid-point of DE.
⇒DF=FE=DE2=42=2 units
In △DIF, DI=IF=DF=2 units
Similarly, in △TKN and △RQU,
TK=KN=TN=RQ=UQ=UR=2 units
it is also clear that, NC=RP=2 units
Also, △HIG is an equilateral triangle.
Here, G is the mid-point of IF.
⇒IG=GF=IF2=22=1 unit
Similarly, in △MLK and △XQS,
ML=MK=LK=SQ=XS=QX=1 unit
it is also clear that, LN=XR=1 unit
Now, perimeter of the given figure
= Sum of all outer sides of the given figure
=AD+DI+IH+HG+GF+FE+EB+BT+TK+KM+LM+LN+NO+OC+CU+UQ+QS+XS+XR+PR+PA
=[4+2+1+1+1+2+4+4+2+1+1+1+2+4+4+2+1+1+1+2+4] cm
=45 cm
Hence, the perimeter of the given figure is 45 cm.