In the given figure- altitude AD bisects - B A C then - B A C is

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The Mid-Point Theorem

In the given ...

Question

In the given figure, altitude AD bisects ∠BAC then ΔBAC is

Obtuse angled triangle

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Isosceles triangle

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Equilateral triangle

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Scalene triangle

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Solution

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Similar questions

In the given figure, if $A D ⊥ B C$ and BD = DC, then AD bisects $∠ B A C$ .

A D

A B C

A B = A C

A D

∠ A

∠ B A C = 90^{\circ}

A D ⊥ B C .

Δ A D C

Δ B A C

A B C

A D

∠ B A C

B A C

B C

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