In the given figure, altitude AD bisects ∠BAC then ΔBAC is
Obtuse angled triangle
Isosceles triangle
Equilateral triangle
Scalene triangle
By ASA criterion, ΔABD ≅ ΔADC.
By c.p.c.t., AB = AC.
Two sides equal, then the triangle is isosceles.
In the given figure, if AD⊥BC and BD = DC, then AD bisects ∠BAC.