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Question

In the given figure, AM BC and AN is the bisector of A. What is the value of MAN?


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Solution

In given figure,
BAC+ABC+ACB=180(Angles of same triangle)BAC+65+33=180BAC=82

CAN=BAC2=41(Given that AN is an angle bisector).Now, CAN+ANC+ACN=180(Angles of same triangle)41+ANC+33=180ANC=106

ANC+ANM=180(Linear pair)106+ANM=180ANM=74

ANM+AMN+MAN=18074+90+MAN=180MAN=16.

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