In the given figure, AM $⊥$ BC and AN is the median from $∠$ A. Then,

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Solution

The correct option is C

In the given figure,
$B N = \frac{1}{2} \times B C$
$\to \frac{1}{2} \times A M \times B N = \frac{1}{2} \times \frac{1}{2} \times A M \times B C$
$\to A r e a (Δ A B N) = \frac{1}{2} \times A r e a (Δ A B C)$
$∴ A r e a (Δ A B C) = 2 \times A r e a (Δ A B N)$

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