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Question

In the given figure, an altitude is drawn to the hypotenuse .The lengths of different segments are marked in the figure. Determine the values of x, y and z in the given case.

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Solution

We have to find the values of x, y, z.

InABC, mABC=90°.Seg BDHypotenuse ACBD2=AD×DC [By property of geometric mean]y2=4×5y=4×5y=25 InADB,mADB=90°AB2=AD2+BD2 [By Pythagoras' Theorem]AB2=42+y2x2=42+(25)2x2=16+20x2=36x=36x=6 InBDC,BC2=BD2+CD2 [By Pythagoras' Theorem]z2=(25)2+52z2=20+25z2=45z=45z=35

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