In the given figure, $∠ 1 = ∠ 2$ and $∠ 3 = ∠ 4$
Show that AD = AB and CD = CB.
[2 marks]

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Solution

$∠ 1 = ∠ 2$ [ Given ]
$∠ 3 = ∠ 4$ [ Given ]
AC = AC [ Common side ]
By ASA congruence criterion, $Δ A D C ≅ Δ A B C$

AD = AB [By CPCT] [1 mark]
CD = CB [By CPCT] [1 mark]

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Question 152 (ii)

In the given figure, $∠ 1 = ∠ 2$ and $∠ 3 = ∠ 4$
Show that AD = AB and CD = CB

∠ 1 = ∠ 2

∠ 3 = ∠ 4

Δ A D C ≅ Δ A B C

{A D}^{2}

\times

In the given figure, $∠ A C B = 90^{o} a n d C D ⊥ A B$ .

Prove that $\frac{B C^{2}}{A C^{2}} = \frac{B D}{A D}$ .

∠ A C B = 90^{0}

C D ⊥ A B

\frac{{C B}^{2}}{{C A}^{2}} = \frac{B D}{A D}

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