In the given figure - ABC -46- then - BAC is equal toA- 42-46-96-D- 92-

From tangent secant theorem, angle in an alternate segment are equal, So ∠ ABC = ∠ BEA = 46^∘ Now, the angle made by chord AB at the centre is double the angle ...

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Standard X

Mathematics

Theorem of Angle between Tangent and Secant

In the given ...

Question

In the given figure $∠ A B C = 46^{\circ},$ then $∠ B A C$ is equal to

42^{\circ}

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46^{\circ}

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92^{\circ}

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96^{\circ}

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Solution

The correct option is C $92^{\circ}$
From tangent secant theorem, angle in an alternate segment are equal, So $∠ A B C = ∠ B E A = 46^{\circ}$
Now, the angle made by chord AB at the centre is double the angle made by chord at circumference,
hence, $∠ B O A = 2 ∠ B E A$
$∠ B O A = 2 \times 46^{\circ}$
$∠ B O A = 92^{\circ}$

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In the given figure ∠ABC=46∘, then ∠BAC is equal to

The correct option is C 92∘From tangent secant theorem, angle in an alternate segment are equal, So ∠ABC=∠BEA=46∘ Now, the angle made by chord AB at the centre is double the angle made by chord at circumference, hence, ∠BOA=2∠BEA ∠BOA=2×46∘ ∠BOA=92∘

In the given figure $∠ A B C = 46^{\circ},$ then $∠ B A C$ is equal to