In the given figure- - ABC is a straight angle- If x - 53- then find y- 147-127-150-37-

The correct option is B 127^∘ Since ∠ABC is a straight angle, its measure = 180^∘. Given: ∠ABD = 53^∘ ∠ABD + ∠DBC = 180^∘ ∴ ∠DBC = 180^∘ 53^∘ = 127^∘ ...

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Standard VI

Mathematics

In the given ...

Question

In the given figure, $∠$ ABC is a straight angle. If x = $53^{\circ}$ , then find y.

$150^{\circ}$

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$147^{\circ}$

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$127^{\circ}$

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$37^{\circ}$

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Solution

The correct option is C
$127^{\circ}$

Since $∠$ ABC is a straight angle, its measure = $180^{\circ}$ .
Given: $∠$ ABD = $53^{\circ}$
$∠$ ABD + $∠$ DBC = $180^{\circ}$
$∴$ $∠$ DBC = $180^{\circ} - 53^{\circ} = 127^{\circ}$

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Standard VI Mathematics

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In the given figure, ∠ ABC is a straight angle. If x = 53∘, then find y.

The correct option is C 127∘ Since ∠ABC is a straight angle, its measure = 180∘. Given: ∠ABD = 53∘ ∠ABD + ∠DBC = 180∘ ∴ ∠DBC = 180∘−53∘=127∘

In the given figure, $∠$ ABC is a straight angle. If x = $53^{\circ}$ , then find y.

The correct option is C
$127^{\circ}$

Since $∠$ ABC is a straight angle, its measure = $180^{\circ}$ .
Given: $∠$ ABD = $53^{\circ}$
$∠$ ABD + $∠$ DBC = $180^{\circ}$
$∴$ $∠$ DBC = $180^{\circ} - 53^{\circ} = 127^{\circ}$