In the given figure- - ACD -120- Find the value of - BCD-A- 40-B- 60-C- 70-D- 80-

The correct option is D 80^∘∠ ACD = ∠ ACB + ∠ BCD ∠ ACD ∠ ACB = ∠ BCD 120^∘ 40^∘ = ∠ BCD ∠ BCD = 80^∘ ...

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In the given ...

Question

In the given figure, $∠ A C D = 120^{\circ}$
Find the value of $∠ B C D$ .

40^{\circ}

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60^{\circ}

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70^{\circ}

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80^{\circ}

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∠ C O E = 90^{o}

Question 19

In the given figure, BC = CA and $∠ A = 40^{\circ}$ . Then, $∠ A C D$ is equal to

a) $40^{\circ}$
b) $80^{\circ}$
c) $120^{\circ}$
d) $60^{\circ}$

∠ B A D = 120^{\circ}

∠ B C D

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∠

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∠

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ABCD is a cyclic quadrilateral, in which $∠$ DBC =80 $^{\circ}$ and $∠$ BAC = 40 $^{\circ}$ . Find $∠$ BCD.

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