Question

In the given figure $\angle ACD$ is a exterior angle of $ABC$ $\angle B={40}^0$ ,$\angle A={70}^0$. Find the measure of $\angle ACD$

Answer 1

$Weknowthat,thesumofexteriorangleisequaltosumofoppositeinteriorangles.$

$\therefore \angle ACD=70+40={110}^{\circ }$