Question

In the given figure, $\angle AOB={90}^o$ and $COD$ is a straight line. The values of $x$ and $y$ are respectively.

• A. ${25}^o$ and ${15}^o$
• B. ${20}^o$ and ${30}^o$
• C. ${15}^o$ and ${45}^o$
• D. ${10}^o$ and ${60}^o$

Answer 1

The correct option is B ${20}^o$ and ${30}^o$

$\angle CDE+\angle EOD={180}^{\circ }$ (CD is straight line)

$\therefore 100+4x=180\left(linearpair\right)\Rightarrow x={20}^{\circ }$

& $3x+90+7=180$ (linear pair)

$\therefore 60+90+y=180$

$y=180-150={30}^{\circ }$