In the given figure ∠ AOC=130∘, The value of ∠ ABC (in degrees) is _______.
Given ∠AOC = 130∘
To find ∠ABC = ?
Construction: Take a point P, anywhere on the circle. Join AP and CP.
Procedure: Subtend ∠A0C at centre and ∠APC at remaining part of the circle.
∠APC = 12 ∠AOC (∠AOC = 130∘) = 12 ×130∘= 65∘
Again, ∠ABC + ∠APC = 180∘
∠ABC + 65∘ = 180∘
∠ABC = 180∘- 65∘ =115∘