Question

In the given figure, $\angle B$ < $\angle A$ and $\angle C$ < $\angle D$. Show that AD < BC.

Answer 1

In $\Delta$ AOB
$\angle B$ < $\angle A$
$\Rightarrow$ AO < BO (side opposite to smaller angle is smaller) ... (1)
Now in $\Delta$COD
$\angle C$ < $\angle D$
$\Rightarrow$ OD < OC (side opposite to smaller angle is smaller) ... (2)
On adding equations (1) and (2), we have
AO + OD < BO + OC
AD < BC