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Question

In the given figure, AOB is a diameter and DC is parallel to AB. If CAB = xo; find (in terms of x) the values of :(i) COB, (ii) DOC, (iii) DAC,(iv) ADC.

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Solution

(i) \angle OCB = 2 \angle CAB = 2x (angles subtended by an chord on the center is double that subtended by the same chord on the circumference)

(ii) \angle OCD = \angle COB = 2 x (alternate angles)

In \triangle OCD

OC = OC (radius of the same circle)

\angle ODC = \angle OCD = 2x

\angle DOC = 180^o-2x-2x = 180^o-4x

(iii) \angle DAC = \frac{1}{2} \angle DOC = \frac{1}{2} (180^o-4x) = 90^o-2x  (angles subtended by an chord on the center is double that subtended by the same chord on the circumference)

(iv) DC \parallel AO (given)

\therefore \angle ACD = \angle OAC = x (alternate angles)

\therefore \angle ADC = 180^o - \angle DAC-\angle ACD = 180^o-(90^o-2x) - x = 90^o+x

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