In the given figure, AOB is a straight line. If ∠AOC = (3x + 10)° and ∠BOC (4x − 26)°, then ∠BOC = ?
(a) 96°
(b) 86°
(c) 76°
(d) 106°

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Solution

(b) 86°

We have :
$∠ A O C + ∠ B O C = 180 ° [Since AOB is a straight line] \Rightarrow 3 x + 10 + 4 x - 26 = 180 ° \Rightarrow 7 x = 196 ° \Rightarrow x = 28 °$

$∴ ∠ B O C = {[4 \times 28 - 26]}^{°} Hence, ∠ B O C = 86 ° .$

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Similar questions

In the given figure, $A O B$ is a straight line. If $∠ A O C = (3 x + 10)^{\circ}$ and $∠ B O C = (4 x - 26)^{\circ}$ , then $∠ B O C = ?$

(a) $96^{\circ}$

(b) $86^{\circ}$

(d) $106^{\circ}$ .

In the given figure, AOB is a straight line. If $∠ A O C = 4 x^{\circ}$ and $∠ B O C = 5 x^{\circ}$ then $∠ A O C = ?$

(a) $40^{\circ}$

(b) $60^{\circ}$

(d) $100^{\circ}$

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