In the given figure $∆ A O D ≅ ∆ B O C$ by ASA congruence condition.

True

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False

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Solution

The correct option is A True
In $∆ A O D$ and $∆ B O C$ ,

$∠ A = ∠ B$ [ Given ]
$A O = B O$ [ Each side $2 c m$ ]
$∠ A O D = ∠ B O C$ [ Vertically opposite angles ]
Therefore, by ASA congruence condition $∆ A O D ≅ ∆ B O C$
Hence, the given statement is true.

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In the given figure ∆AOD≅∆BOC by ASA congruence condition.

The correct option is A TrueIn ∆AOD and ∆BOC, ∠A=∠B [ Given ] AO=BO [ Each side 2cm ]∠AOD=∠BOC [ Vertically opposite angles ]Therefore, by ASA congruence condition ∆AOD≅∆BOCHence, the given statement is true.

In the given figure $∆ A O D ≅ ∆ B O C$ by ASA congruence condition.

The correct option is A True
In $∆ A O D$ and $∆ B O C$ ,

$∠ A = ∠ B$ [ Given ]
$A O = B O$ [ Each side $2 c m$ ]
$∠ A O D = ∠ B O C$ [ Vertically opposite angles ]
Therefore, by ASA congruence condition $∆ A O D ≅ ∆ B O C$
Hence, the given statement is true.