In the given figure $A P = 12$ , $R P = 4$ , $P S = 6$ . Find $B S$

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Solution

From figure,
$Δ P A B \sim Δ P R S$
$⟹ \frac{A P}{R P} = \frac{B P}{P S} B P = \frac{12}{4} \times 6 = 18 B P = P S + B S B S = 18 - 6 = 12 c m$

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