In the given figure, AP and AQ are two tangent drawn from a point outside the circle. Select the correct option from the following.

∠

PAO <

∠

QAO

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∠

PAO >

∠

QAO

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∠

PAO =

∠

QAO

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∠

PAO = 2

∠

QAO

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Solution

The correct option is C $∠$ PAO = $∠$ QAO
By theorem: The centre of a circle lies on the bisector of the angle between two tangents.
so, AO is a bisector to $∠$ PAQ
$∴$ $∠$ PAO = $∠$ QAO

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∠

In the given figure, a circle touches the side BC of Δ A B C at P. AR and AQ are two tangents drawn from a point A outside the circle. If AQ = 15 cm, find the perimeter of Δ A B C (in cm) .

In the given figure, a circle touches the side BC of Δ A B C at P. AR and AQ are two tangents drawn from a point A outside the circle. If AQ = 15 cm, find the perimeter of Δ A B C (in cm) .

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