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Question

In the given figure, AP BQ CR. What will be ar(AQC)?

A
ar(ABQ)
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B
ar(CQR)
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C
ar(PQA)
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D
ar(PBR)
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Solution

The correct option is D ar(PBR)

Since △ABQ and △PBQ lie on the same base BQ and are between the same parallels AP and BQ,

∴ Area (△ABQ) = Area (△PBQ) ... (1)

Again, △BCQ and △BRQ lie on the same base BQ and are between the same parallels BQ and CR.

∴ Area (△BCQ) = Area (△BRQ) ... (2)

On adding equations (1) and (2), we obtain

Area (△ABQ) + Area (△BCQ) = Area (△PBQ) + Area (△BRQ)

⇒ Area (△AQC) = Area (△PBR)


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