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Question

In the given figure, APB and AQO are semicircles and AO = OB. If the perimeter of the figure is 40 cm, find the area of the shaded region.

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Solution

so for this figure, there are 2 semicircles APB and AQO

as AO=OB=r ( given)

Perimeter of shaded region = circumference of semicircle APB + circumference of semicircle AQO
40 =π( r +r over 2)

80 = 3 rπ
r= fraction numerator 80 over denominator 3 straight pi end fraction ...........1

Now Area of shaded region =
πr squared plus straight pi open parentheses straight r over 2 close parentheses squared equals 5 straight pi straight r squared over 4

Putting value of r from 1

=5 straight pi open parentheses begin display style fraction numerator 80 over denominator 3 straight pi end fraction end style close parentheses squared over 4

we get area of shaded region as 283.09c m squared


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