In the given figure arc AB and arc CD of a circle having centre at O are equal to 5cm.If $∠ A O B = 40^{\circ}$ , then the $∠ C O D$ is equal to__.

30^{\circ}

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40^{\circ}

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50^{\circ}

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60^{\circ}

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Solution

The correct option is B $40^{\circ}$
In the figure arc AB = CD = 5cm.
Since $∠ A O B = 40^{\circ}$ , $∠ C O D$ will also be equal to $40^{\circ}$

(Two equal arcs subtend equal angle at the centre)

Hence, $∠ C O D = 40^{\circ}$

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