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Byju's Answer
Standard IX
Mathematics
Parallel Lines with Transversal
In the given ...
Question
In the given figure
A
S
∥
B
T
;
∠
4
=
∠
5
¯
S
B
bisects
∠
A
S
T
.find the measure of
∠
1
A
∠
1
=
80
∘
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B
∠
1
=
60
∘
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C
∠
1
=
70
∘
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D
∠
1
=
20
∘
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Solution
The correct option is
B
∠
1
=
60
∘
Given,
∠
4
=
∠
5
⟹
∠
3
=
∠
4
=
∠
5
=
60
∘
--- if 2 angles are equal, then they are equal to third.
Given,
S
B
is the bisector of
∠
A
S
T
⇒
∠
B
S
T
=
∠
A
S
B
=
60
∘
∠
R
S
T
=
∠
R
S
A
+
∠
A
S
B
+
∠
B
S
T
=
180
∘
--- angles on a straight line
⇒
∠
R
S
A
=
180
∘
−
60
∘
−
60
∘
=
60
∘
∴
∠
1
=
60
∘
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Standard IX Mathematics
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