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Byju's Answer
Standard XII
Physics
Problem Solving
In the given ...
Question
In the given figure, at the free end a force
F
is applied to keep the suspended mass of
18
k
g
at rest. The value of
F
(in
N
) is
Take
(
g
=
10
m
/
s
2
)
Open in App
Solution
As the string is same, the force applied will be transmitted undiminished as tension in the whole string as shown in the figure.
Hence, from the FBD of the pulley and mass of
18
k
g
, we have for equilibrium condition
T
=
2
F
And,
T
=
18
g
=
180
⇒
2
F
=
180
⇒
F
=
90
N
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