Question

In the given figure, at the free end a force $F$ is applied to keep the suspended mass of $18kg$ at rest. The value of $F$ (in $N$) is
Take $(g=10m/s^2)$

Answer 1

As the string is same, the force applied will be transmitted undiminished as tension in the whole string as shown in the figure.


Hence, from the FBD of the pulley and mass of $18kg$, we have for equilibrium condition

$T=2F$
And, $T=18g=180\Rightarrow 2F=180\Rightarrow F=90N$