In the given figure at the free end of the light string, a force F is applied to keep the suspended mass of 18kg at rest. Assuming pulley is light and frictionless, then the force exerted by the ceiling on the system is
A
120N
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B
360N
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C
240N
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D
60N
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Solution
The correct option is C240N Here, 3T=18g=18(10)=180 ∴T=60N also F=T=60N ∴ The total force exerted by the ceiling on the system =F+T+T+T=60+60+60+60=240N