Question

In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.

Answer 1

Given that ∠B < ∠A; ∠C < ∠D

∠B < ∠A $\Rightarrow$ AO < OB [in $\Delta$AOB] ……………… (1)

∠C < ∠D $\Rightarrow$ OD < OC [in $\Delta$COD]…… (2)

Adding (1) & (2)

AO + OD < OB + OC

AD < BC

Hence proved.