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Question

In the given figure, BAAC, DEDF, such that, BA=DE, BF=EC. Then, ABCDEF by which congruence rule?


  1. SAS

  2. SSS
  3. RHS
  4. ASA


Solution

The correct option is C RHS

BC=BF+FC and FE=FC+EC

Since, FC is common to both sides, and BF=EC  [given]

Therefore, BC=FE

Now, in ABC and DEF,

BC=FE  [proved]

AB=DE  [given]

BAC=EDF=90  [given]

Therefore, ABCDEF  [by RHS congruence condition]

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