Question

In the given figure, $BC\perp AB,AD\perp AB,BC=4,AD=8,$ then find $\frac{A\left(\Delta ABC\right)}{A\left(\Delta ADB\right)}$.

Answer 1

Given:
$BC=4$
$AD=8$

$BC\perp AB,AD\perp AB$

We know that area of right angled triangle $=\frac{1}{2}\times$ Base $\times$ height

$\therefore \frac{A\left(\Delta ABC\right)}{A\left(\Delta ADB\right)}=\frac{\frac{1}{2}AB\times BC}{\frac{1}{2}AB\times AD}=\frac{BC}{AD}=\frac{4}{8}=\frac{1}{2}$