In the given figure, BD bisects ∠ABC and BD is perpendicular to AC. If the lengths of the sides of the triangle are expressed in terms of x and y as shown, then x =
x=3,y=7
In ΔABD and ΔCBD
(i) ∠ABD=∠CBD ... (given )
(ii) BD=BD……(common)
(iii) ∠BDA=∠BDC=90∘ ….(given)
∴ΔABD≅ΔCBD (ASA postulate)
⇒AD=DC ……..(CPCT)
5x–3=2x+63x=9x=3
and BA=BC ……..(CPCT)
2y–1=132y=14y=7