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Question

In the given figure, CD and AB are intersecting chords and EF is a tangent to the circle. If OD = 4 cm, OB = 12 cm, OA = 4 cm and DE = 4 cm, then the length of EF is equal to


A

105
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B

45
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C

25
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D

65
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Solution

The correct option is B
45
Given: OD = 4 cm, OB = 12 cm, OA = 4 cm, DE = 4 cm

Also, it is given that CD and AB are intersecting chords and EF is tangent to the circle.



AB and CD are the intersecting chords.

OC×OD=OB×OAOC×4=12×4OC=12 cm

Apply Tangent Secant Theorem
EF2=ED×ECEF2=4×20(EC=DE+OD+OC) EF=45 cm

Thus, the length of EF is 45 cm

Hence, the correct answer is option b.

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