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Question

In the given figure, chords AB and CD when extended meet at P. If AB = 4 cm, BP = 6 cm, DP = 5 cm, then find the value of CD.


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Solution



If two chords intersect externally, then PA×PB=PC×PD

10×6=PC×5 ........ (PA = AB + BP)

PC = 12 cm

CD + DP = 12 cm

CD = 12 – 5 ......... (DP = 5cm)

CD =7 cm

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