We know that equal chords of a circle subtend equal angles at the centre.
⇒∠POQ=∠ROS=75∘
Since, the central angle of a circle is 360∘
So, ∠POQ+∠QOR+∠ROS+∠POS=360∘
⇒75∘ +∠QOR+75∘ +150∘ =360∘
⇒300∘ +∠QOR=360∘
⇒∠QOR=360∘ −300∘ =60∘
The given figure shown a circle with centre O. Also, PQ = QR = RS and ∠ PTS = 75o. Calculate :
(i) ∠ POS,
(ii) ∠ QOR,
(iii) ∠ PQR.