In the given figure- CO - OD - OCD -30- Find - AOB- -3 MARKS-

Concept: 1 Mark Steps: 1 Mark Answer: 1 Mark Sum of the angles of a triangle is 180^∘. Since OC = OD, ∠ OCD = ∠ ODC = 30^∘ [Angles opposite to equal sides ar ...

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Standard VII

Mathematics

Angles

In the given ...

Question

In the given figure, CO = OD & $∠ O C D = 30^{\circ}$ . Find $∠ A O B$ ? [3 MARKS]

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Solution

Concept: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Sum of the angles of a triangle is $180^{\circ}$ .

Since OC = OD, $∠ O C D = ∠ O D C = 30^{\circ}$
[Angles opposite to equal sides are equal]

$\Rightarrow ∠ C O D = 180^{\circ} - (30^{\circ} + 30^{\circ}) = 120^{\circ}$

$∠ A O B = ∠ C O D$ [Vertically Opposite Angles]

$∴ ∠ A O B = 120^{\circ}$

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In the given figure, CO = OD & ∠OCD=30∘. Find ∠AOB? [3 MARKS]

Concept: 1 Mark Steps: 1 Mark Answer: 1 Mark Sum of the angles of a triangle is 180∘. Since OC = OD, ∠OCD=∠ODC=30∘ [Angles opposite to equal sides are equal] ⇒∠COD=180∘−(30∘+30∘)=120∘ ∠AOB=∠COD [Vertically Opposite Angles] ∴∠AOB=120∘

In the given figure, CO = OD & $∠ O C D = 30^{\circ}$ . Find $∠ A O B$ ? [3 MARKS]