In the given figure- D and E are mid points of sides AB and AC of ABC- Which of the following is true-A- DE -1-2 BC- by converse of mid point theoremB- DE -1-0 AB- by mid point theoremC- DE -1- AB- by converse of mid point theoremD- DE -1-2 BC- by mid point theorem

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Congruence of Triangles

In the given ...

Question

In the given figure, D and E are mid points of sides AB and AC of $△$ ABC. Which of the following is true?

DE = BC, by mid point theorem

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DE = BC, by converse of mid point theorem

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DE = AB, by mid point theorem

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DE = AB, by converse of mid point theorem

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Solution

The correct option is A
DE = BC, by mid point theorem

Mid point theorem states that a line joining the mid points of 2 sides of a triangle is parallel to the third side and is half of it.

Therefore, by mid point theorem, DE = $\frac{1}{2}$ BC and DE ||BC

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In the given figure, D and E are mid points of sides AB and AC of △ABC. Which of the following is true?

The correct option is A DE = BC, by mid point theorem Mid point theorem states that a line joining the mid points of 2 sides of a triangle is parallel to the third side and is half of it. Therefore, by mid point theorem, DE = 12 BC and DE ||BC

In the given figure, D and E are mid points of sides AB and AC of $△$ ABC. Which of the following is true?

The correct option is A
DE = BC, by mid point theorem

Mid point theorem states that a line joining the mid points of 2 sides of a triangle is parallel to the third side and is half of it.

Therefore, by mid point theorem, DE = $\frac{1}{2}$ BC and DE ||BC